Question

A straight pipe carried water from reservoir(R) to a tap(T) and T are 2km a part horizontally and R 500m above the level.find lenght of the pipe.

Answer 1

hypotenuse

Answer 2

How can I solve this

Answer 3

Have no experience

Answer 4

A straight pipe carried water from reservoir(R) to a tap(T) and T are 2km a part horizontally and R 500m above the level.find lenght of the pipe.

Answer 5

[AI-generated answer — Explain Bot]

To find the length of the pipe, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, we can consider the distance between the reservoir (R) and the tap (T) as the hypotenuse of a right-angled triangle, and the vertical distance (500m) as one of the sides. The horizontal distance (2km or 2000m) is the other side.

Using the Pythagorean theorem:

Length of the pipe = √(horizontal distance^2 + vertical distance^2)

Substituting the values:

Length of the pipe = √(2000m^2 + 500m^2)
= √(4000000m^2 + 250000m^2)
= √(4250000m^2)
≈ 2061.55m

Therefore, the length of the pipe is approximately 2061.55 meters.