Physics

A man with a mass(mm) of 71.9 kg stands up in a 95-kg canoe(mc) of length(l) 4.00 m floating on water. He walks from a point 0.75 m from the back of the canoe to a point 0.75 m from the front of the canoe. Assume negligible friction between the canoe and the water. How far does the canoe move?

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  1. No external forces on system so center of mass continues at constant speed of zero so does not move

    how far did he walk in the canoe?
    4.00 - 1.5 = 2.5 m

    distance he moved * his mass = distance canoe moved * its mass

    2.5 *71.9 = 95 x

    x = 2.5 * 71.9 / 95

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