Calculus

A base of a solid is the region bounded by y=e^-x, the x axis, the y axis, and the line x=2. Each cross section perpendicular to the x-axis is a square Find the volume of the solid

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  1. So, each square has base and height e^-x

    Thus, the volume, adding up all those thin squares, is

    ∫[0,2] (e^-x)^2 dx
    = ∫[0,2] e^(-2x) dx
    let u = 2x, and that becomes
    (1/2)∫[0,4] e^-u du
    ...

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  2. so would it be 1/2(1-(1/e^4))

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