Quadratic Functions1
Determine the x intercepts, y intercept, equation of the axis of symmetry and vertex for each of the following functions,
1.) f(x)= 3(x2)^26 with zeros of 0.59 and 3.41
2.) g(x)= (x4)(x+7)

1. f(x)= 3(x2)^26 with zeros of 0.59 and 3.41
everything you asked for , except the yintercept, can simply be stated directly from the equation:
xintercepts, you stated them already
axis of symmetry: x2 = 0 or x = 2
vertex: (2,6)
for the yintercept, let x = 0
y = 3(2)^2  6 = 6
g(x) = (x4)(x+7)
x intercepts: x = 4 and x = 7
the vertex is halfway between 4 and 7
so the x of the vertex is (7+4)/2 = 3/2
sub that in ...
y = (3/2  4)(3/2 + 7) = 121/4
vertex is (3/2 , 121/4)
axis of symmetry : x = 3/2
yintercept: let x = 0
y = (4)(7) = 28posted by Reiny
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