Quadratic Functions1

Determine the x intercepts, y intercept, equation of the axis of symmetry and vertex for each of the following functions,
1.) f(x)= 3(x-2)^2-6 with zeros of 0.59 and 3.41
2.) g(x)= (x-4)(x+7)

asked by Heaven
  1. 1. f(x)= 3(x-2)^2-6 with zeros of 0.59 and 3.41

    everything you asked for , except the y-intercept, can simply be stated directly from the equation:
    x-intercepts, you stated them already
    axis of symmetry: x-2 = 0 or x = 2
    vertex: (2,-6)

    for the y-intercept, let x = 0
    y = 3(-2)^2 - 6 = 6

    g(x) = (x-4)(x+7)
    x intercepts: x = 4 and x = -7
    the vertex is half-way between 4 and -7
    so the x of the vertex is (-7+4)/2 = -3/2
    sub that in ...
    y = (-3/2 - 4)(-3/2 + 7) = -121/4
    vertex is (-3/2 , -121/4)
    axis of symmetry : x = -3/2
    yintercept: let x = 0
    y = (-4)(7) = -28

    posted by Reiny

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