What is the y-coordinate of the y-intercept of the linear equation 2x - 3y = 12?
Plz help I don't understand how to do this can you show me step by step plz, sorry ;-;
easiest way:
for the y-intercept, let x = 0 , (can be done mentally)
so -3y=12 ----- > y = -4
You are probably using the equation in the form
y = mx +b, where b is the y-intercept, so change your given equation to that form
2x - 3y = 12
-3y = -2x + 12
divide by -3
y = (2/3)x - 4 , what do you see instead of b ?
Of course! I'd be happy to help you understand how to find the y-coordinate of the y-intercept for the given linear equation.
Step 1: The y-intercept represents the point at which the line intersects the y-axis, which occurs when x is equal to 0. So, in order to find the y-coordinate of the y-intercept, we need to substitute x = 0 into the equation and solve for y.
Step 2: In the given equation, 2x - 3y = 12, substitute x with 0. The equation becomes:
2(0) - 3y = 12
Simplifying this equation gives us:
-3y = 12
Step 3: To solve for y, divide both sides of the equation by -3 to isolate y:
-3y / -3 = 12 / -3
This simplifies to:
y = -4
Therefore, the y-coordinate of the y-intercept for the given linear equation 2x - 3y = 12 is -4.