A car accelerates from rest at 1.1+2(t^1/2) m/h per second for 9 seconds find velocity after 9 seconds.
a = 1.1+2(t^1/2)
v = 1.1t + (2/(3/2)) t^(3/2) + c
v = 1.1t + (4/3)t^(3/2) + c
when t = 0 , v = 0
0 = 0 + 0 + c -----> c = 0
v = 1.1t + (4/3) t^(3/2)
when t = 9
v = 1.1(9) + (4/3) (9)^(3/2)
= 9.9 + (4/3)(27)
= 9.9 +36
= 45.9 m/h