an agriculture field is rectangular, with dimensions 100m by 42m.a 20 m deep well of diameter 14 m is dug in a corner of the field and the earth taken out is spread evenly over the remaining part of the field.find the increase in the level of the field
Volume Of well=22/7×7×7×20
=3,080m^3
Area Of filed =100×42= 4200m^2
The area of the remaning part of the filed=the area of field - the area of well, so. 4200m^2 - 154m^2 (22/7×7×7)=4046m^2
The volume of the riseing filed = the volume of the earth dug out
4046(h)=3080m^3
h=0.7612'm
=76cm።።።።just like hizki..
76
volume of well = π r^2 h
= π(7^2)(20)
= 98π m^3
surface area to be covered by dirt
= 100(42) - π(7^2)
=4200 - 49π m^2
let the depth of the dirt be h m
(4200 - 49π)h = 98π
check and do my arithmetic
Sorry , the answer is mighty 76.please help me! I am in confusion.!!!!!
You are really correct. My response is just like u.
(toliyad) the answer is 76cm dude
0.076
yes
calculate the volume and surface area of a right circular cylinder of height 1m and 70cm
The level of the field increased by 76 cm.
76
To calculate the volume of a right circular cylinder, we use the formula:
V = πr²h
where r is the radius of the base and h is the height of the cylinder.
Given: Height h = 1.7 m
The radius is not given, so we cannot calculate the volume.
To calculate the surface area of a right circular cylinder, we use the formula:
A = 2πrh + 2πr²
where r is the radius of the base and h is the height of the cylinder.
Given: Height h = 1.7 m
The radius is not given, so we cannot calculate the surface area.