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algebra 2b

A simple random sample of 50 adults was surveyed, and it was found that the mean amount of time that they spend surfing the Internet per day is 54.2 minutes, with a standard deviation of 14.0 minutes. What is the 99% confidence interval (z-score = 2.58) for the number of minutes that an adult spends surfing the Internet per day?

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kevin

  1. 99% = mean ± Z SEm

    SEm = SD/√n

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    PsyDAG

  2. 50min

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    Anonymous

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