I AM A NUMBER. ROUNDING TO THE NEAREST THOUSAND MAKES ME 1,000. ALL MY DIGITS ARE EVEN, THEIR SUM IS 12, THEY ARE IN ORDER FROM GREATEST TO LEAST, AND NO DIGIT IS REPEATED. WHAT NUMBER AM I?
Between 500 and 1499 so three or 4 digits.
Try 3
864 no
642 ah hah
642
To find the number that meets these criteria, we can start by thinking about the possible values for the thousands digit. Since rounding to the nearest thousand makes the number 1,000, we know that the thousands digit must be either 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9.
Given that the digits are in order from greatest to least, we can eliminate 0 as a possibility for the thousands digit. Now let's consider the possible values for the hundreds digit. Since the sum of all the digits is 12 and they are all even, the only possibilities for the hundreds digit are 4 or 6.
If we assume that the hundreds digit is 4, then the remaining digits must be 8, 6, and 2. However, this would not satisfy the condition that no digit is repeated. Therefore, the hundreds digit must be 6.
Now we know the thousands digit is not 0 and the hundreds digit is 6. With the sum of all digits being 12, there are only two remaining even digits: 4 and 2. Considering the condition that no digit is repeated and the digits are in order from greatest to least, we can conclude that the number you are is 6426.