Find the equation in standard form for the hyperbola that satisfies the given conditions: transverse axis endpoints (-2,-2) and (-2,7), slope of one asymptote 4/3. I found the distance of the transverse axis to be 9. For the
The equation of the hyperbola is (x-3)^2/4 - (y+1)^2/16 =-1. What is the range? All I know is this but I am not even sure what I am doing!! My answer: The general form of the equation of a horizontally aligned hyperbola is:
Find the equation of the hyperbola. Transverse axis parallel to the x-axis, center at (5,1), the rectangle on the axes of the hyperbola of area 48 and distance betwern foci 10. i do nt know how . sorry . pls do help me ..
HELP! I am not sure how I would even start this problem or solve it. A hyperbola with a horizontal transverse axis contains the point at (4, 3). The equations of the asymptotes are y-x=1 and y+x=5 Write an equation for the
Please help I can't figure out these two. Express f(x) in the form a(x − h)2 + k. f(x) = −4x2 + 24x − 9 Find the standard equation of a parabola that has a vertical axis and satisfies the given conditions. vertex