The temperature of a silver bar rises by 10. 0°c when it absorbs 1230 jof energy by heat. The made of the bar is 525 g. Determine the specific heat of silver.
To determine the specific heat of silver, we can use the formula:
Heat (Q) = mass (m) × specific heat (c) × change in temperature (ΔT)
Let's plug in the given values:
Q = 1230 J
m = 525 g
ΔT = 10.0 °C
Now we can rearrange the formula to solve for the specific heat (c):
c = Q / (m × ΔT)
Substituting the values, we get:
c = 1230 J / (525 g × 10.0 °C)
To obtain the specific heat in units of J/g·°C, we need to convert 525 g to kilograms (kg):
c = 1230 J / (0.525 kg × 10.0 °C)
Simplifying the calculation, we have:
c ≈ 234.29 J/g·°C
Therefore, the specific heat of silver is approximately 234.29 J/g·°C.