It is given that cos^2 y + cos y = p . Determine the value of p if sin y = sin y . Cos y
Are you using the . in siny.cosy as a multiplication sign?
If so, then
siny = sinycosy
cosy = 1
and cos^2 y + cosy = p
1+1 = p
p = 2
Am I missing something here??
Looks too easy, did you have a typo?
of course , if siny = 0, then we have cosy = 1 or -1.
You can try those for other solutions.
To determine the value of p, we need to use the given equation cos^2 y + cos y = p and the equation sin y = sin y . Cos y.
First, let's simplify the equation sin y = sin y . Cos y:
sin y = sin y . Cos y
Divide both sides by sin y:
1 = cos y
Now we know that cos y = 1.
Next, let's substitute this value of cos y into the first equation cos^2 y + cos y = p:
(1)^2 + 1 = p
Simplifying:
1 + 1 = p
2 = p
Therefore, the value of p is 2.