A rectangular fence has a perimeter of 1080 feet. The length is 3 feet more than twice the width. I need to know the dimensions and how to figure it out.
width: w
length: 2w+3
so 2w + 2(2w+3) = 1080
solve
I am sure you can take it from here.
how do you do two step equations
don't know what you mean by 'two step' equations but here is how I would continue
2w + 2(2w+3) = 1080
2w + 4w + 6 = 1080
6w = 1080 - 6
6w = 1074
w = 179
then length = 2w + 3 = 2(179) + 3 = 361
To find the dimensions of the rectangular fence, we can set up a system of equations based on the given information.
Let's assume the width of the fence is "x" feet. According to the problem, the length is 3 feet more than twice the width. So, the length can be represented as "2x + 3" feet.
The formula for the perimeter of a rectangle is given by P = 2L + 2W, where P is the perimeter, L is the length, and W is the width.
Substituting the given values, we have:
1080 = 2(2x + 3) + 2x
Simplifying the equation, we get:
1080 = 4x + 6 + 2x
Combining like terms, we have:
1080 = 6x + 6
Now, we can isolate the variable:
1080 - 6 = 6x
1074 = 6x
Dividing both sides by 6:
x = 1074 / 6
x = 179
So, the width of the rectangular fence is 179 feet. Now we can find the length by substituting the value of the width into the given formula:
Length = 2x + 3
Length = 2(179) + 3
Length = 358 + 3
Length = 361
Therefore, the dimensions of the rectangular fence are 179 feet by 361 feet.