0.75 L of a 48.5 %V/V methanol solution is diluted to make 5.60 L of solution. What is the final concentration of this solution?

48.5% x (0.75L/5.60L) = ?%

Thanks

To find the final concentration of the solution, we can use the formula:

C1V1 = C2V2

Where:
C1 = Initial concentration
V1 = Initial volume
C2 = Final concentration
V2 = Final volume

In this case, we are given:
C1 = 48.5% V/V (which can also be written as 0.485)
V1 = 0.75 L
C2 = ?
V2 = 5.60 L

Now we can substitute these values into the formula and solve for C2:

C1V1 = C2V2
(0.485)(0.75) = C2(5.60)
0.364 = C2(5.60)
C2 = 0.364 / 5.60
C2 ≈ 0.065

Therefore, the final concentration of this solution is approximately 0.065 or 6.5% V/V.