A car went 60 km in 5/6 of an hour while a second car went 54 km in 2/3 hour. Which car was faster? How many times faster?
The answer is 1.125.
Car A went 60 km in 5/6 of an hour while a car B went 54 km in 2/3 of an hour. Which car was faster? How many times faster?
Solution:
To find Speed we need to divide Distance by Time.
Speed of car A is 60km ÷ 5/6= 1.2
Speed of car B is 54km ÷ 2/3= 1.35
Car B is faster.
To answer how many times faster we need to divide the Speed of car B by the speed of car A.
1.35 ÷ 1.2= 1.125
The second car went faster then the first car by 1.125!
60km divided by 5/6=1.2
54km divided by 2/3= 1.35
1.35 divided by 1.2..?
That equals...1.125!
1.125
Car A went 60 km in 5 6 hour while a car B went 54 km in 2 3 hour. Which car was faster? How many times faster? HALP
noice
the second car
faster by how many times
Please Help! By how much faster did the second car go?
How much faster did the second car go
the second car by x amount
wich car went faster
by how much did faster did the second cr go
Its Rate x Time = Distance
60 x 5/6 = 300/6 = 50km
54 x 2/3 = 108/3 = 36km
1/3 = 18km
1/6 = 10km
The second car went faster
10 x 6 = 60km/per hour
18 x 3 = 54km/per hour
and then idk man
60(1-5/6) = 60(1/6) = 10
60 + 10 = 70
60 km in 5/6 hour = 70km/hr
54(1-2/3) = 54(1/3) = 18
54 + 18 = 72
54km in 2/3 hour = 72km/hr
72/70 = ?