chemistry

If 17.5 mL of 0.553 M KOH is needed to neutralize 25.0 mL of an HBr solution what is the molarity od HBr solution

asked by rosie
  1. moles KOH = .0175 * .553 = .00968

    so, you need that many moles of HBr, making the molarity

    M = .00968/.025 = 0.387

    posted by Steve

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