Solving for x
- 👍 0
- 👎 0
- 👁 58
Respond to this Question
Similar Questions
-
Calculus
Please look at my work below: Solve the initial-value problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/- Sqrt(4^2-4(1)(6)))/2(1) r=(16 +/- Sqrt(-8)) r=8 +/- Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2,
asked by COFFEE on July 10, 2007 -
Calculus - Second Order Differential Equations
Posted by COFFEE on Monday, July 9, 2007 at 9:10pm. download mp3 free instrumental remix Solve the initial-value problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/- Sqrt(4^2-4(1)(6)))/2(1) r=(16 +/- Sqrt(-8))
asked by COFFEE on July 10, 2007 -
Trig/Precalc
So I have two questions that have been puzzling me for quite some time and would really appreciate any help with either of them! (a) There are four positive intergers a, b, c, and d such that
asked by majorbill on January 4, 2015 -
Math/Calculus
Solve the initial-value problem. Am I using the wrong value for beta here, 2sqrt(2) or am I making a mistake somewhere else? Thanks. y''+4y'+6y=0, y(0)=2, y'(0)=4 r^2+4r+6=0, r=(-4 +/- sqrt(16-4(1)(6))/2 r=-2 +/- sqrt(2)*i , alpha
asked by COFFEE on July 12, 2007 -
URGENT - Trigonometry - Identities and Proofs
Okay, today, I find myself utterly dumbfounded by these three questions - Write a proof for - 2/(sqrt(3)cos(x) + sin(x))= sec((pi/6)-x) Solve the following equation - 2sin(2x) - 2sin(x) + 2(sqrt(3)cos(x)) - sqrt(3) = 0 Find all
asked by Veronica on April 2, 2011 -
Calculus - Second Order Differential Equations
Solve the initial-value problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/- Sqrt(4^2-4(1)(6)))/2(1) r=(16 +/- Sqrt(-8)) r=8 +/- Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2, e^(8*0)*(c1*cos(0)+c2*sin(0))=c2=2
asked by COFFEE on July 9, 2007 -
Vectors
The angle between the vectors a=(6,-2,3) and b=(1,p,-2) is cos^-1(-1/14). Determine the value of p. |a|=sqrt(6^2+(-2)^2+3^2)=7 |b|=sqrt(1^2+p^2+(-2)^2)=5+p^2 theta=cos(cos^-1(-1/14))=-1/14 a x b = (4-3p,15,6p+2) a x b =
asked by Anonymous on June 19, 2018 -
math
A trigonmetric polynomial of order n is t(x) = c0 + c1 * cos x + c2 * cos 2x + ... + cn * cos nx + d1 * sin x + d2 * sin 2x + ... + dn * sin nx The output vector space of such a function has the vector basis: { 1, cos x, cos 2x,
asked by mathstudent on January 16, 2008 -
calc
find the area between the x-axis and the graph of the given function over the given interval: y = sqrt(9-x^2) over [-3,3] you need to do integration from -3 to 3. First you find the anti-derivative when you find the
asked by mikayla on April 18, 2007 -
Precalculs
I have no idea how to do these type of problems. -------Problem-------- Solve each equation on the interval 0 less than or equal to theta less than 2 pi 42. SQRT(3) sin theta + cos theta = 1 ---------------------- There is an
asked by Kate on February 28, 2010