Each of two urns contains green balls and red balls. Urn I contains 8 green balls and 12 red balls. Urn II contains 5 green balls and 8 red balls. If a ball is drawn from each urn, what is P(red and red)?
A. 79/65
B. 24/65
C. 20/33*
D. 2/13
You have six $1 bills, eight $5 bills, two $10 bills, and four $20 bills in your wallet. You select a bill at random. Without replacing the bill, you choose a second bill. What is P($1, then $10)?
A. 77/190*
B. 3/100
C. 3/95
D. 2/5
A true-false test has 12 questions. What is the probability of guessing the correct answers to all of the questions?
A. 1/4096
B. 1/144*
C. 1/24
D. 1/14
Please check these. If I'm incorrect, please help because I'm very stumped. :-( Thank you very much!
For the first one, I think it is B
P(red and red) = 12/20 * 8/13
(Don't forget to add the total number of balls)
Second one is C
P(1 then 10) = 6/20 * 2/19
Since you take one note without replacing, the total number of notes is reduced by 1 from 20 to 19
The third one is A
P(one question right) = 1/2
(2 options, T or F)
P(12 questions right) = 1/2 * 12
I would Multiply 1/2 by 12 (instead of add 1/2 12 times)here because it is in one whole test paper (haha not too sure how to explain, if it is confusing, just ignore it)
Hope this helps!
His name is Saitama
DaKoolKid...thanks but unfortunately, many of your answers seem incorrect :/
she is not she has posted these answers in many different questions on here and everyone has said that her answers are wrong. do not follow lady usanes answers
i read that as watch dragon balls lol
y u takin credit of other peopls speech mf
no. u can stay clueless mf
1)
prob(r,r) = (12/20)(8/13) = 24/65 ----> B
2)
prob = (6/20)(2/19) = 3/95 ----> C
3)
you want (1/2)^12 = 1/4096 ----> A
I'm sorry, I'm not sure what you're referring to. As an AI language model, I don't take credit for anyone's speech, as everything I say is generated based on algorithms and programming. Can you please clarify your question or concern?
I'm sorry if I offended you in any way. As an AI language model, I'm programmed to assist and provide information to the best of my abilities. Please let me know if there's anything else I can help you with.
Each of two urns contains green balls and red balls. Urn I contains 8 green balls and 12 red balls. Urn II contains 5 green balls and 8 red balls. If a ball is drawn from each urn, what is P(red and red)?
A. 79/65
B. 24/65
C. 20/33*
D. 2/13
The probability of drawing a red ball from urn I is 12/20, and the probability of drawing a red ball from urn II is 8/13. The probability of both events happening (drawing a red ball from each urn) is the product of their probabilities:
P(red and red) = (12/20) * (8/13) = 96/260 = 24/65
Therefore, the answer is (B) 24/65.
If you spin the spinner below twice, what is P(vowel, then Q)?
I'm sorry, but I don't see a spinner image attached. Could you please provide more details or context to the problem?
bot can u help
Of course! Please provide the necessary information for the problem you need help with and I'll do my best to assist you.
a. What is the probability of selecting a red marble, replacing it, and then selecting a blue marble? Show your work.
b. What is the probability of selecting a red marble, setting it aside, and then selecting a blue marble? Show your work.
Are the answers to parts (a) and (b) the same? Why or why not?
The probability of selecting a red marble from a bag of marbles containing 4 red, 2 blue, and 3 green marbles is 4/9. We can calculate the probability of selecting a blue marble in two ways, depending on whether the marbles are replaced:
a. With replacement: The probability of selecting a blue marble after selecting a red marble and replacing it is also 2/9, since the probability of selecting a blue marble on each draw is independent of the other.
P(red, then blue) = (4/9) * (2/9) = 8/81
b. Without replacement: If the red marble is set aside and not replaced, the probability of selecting a blue marble on the second draw depends on whether the red marble was selected or not. If the red marble was selected on the first draw, then there are only 8 marbles left in the bag, 1 of which is blue. The probability of selecting this blue marble is 1/8.
P(red, then blue) = (4/9) * (1/8) = 1/18
No, the answers to parts (a) and (b) are not the same because without replacement, there are different numbers of marbles remaining in the bag, which changes the probability of selecting a blue marble on the second draw.
Haha, no worries!
whatch dragon ball z
I figured out number one, which would be 2/13.
is lady unsane right?
1. A
2. C
3. B
4. B
5. C
6. B
7. B
8. C
9. D
10. B
11. C
12. C
13. D
14. A
15. A
16. C
17. A
18. C
i got 12/18 searching the answers one by one.
these should get you 100%
1.A
2.C
3.B
4.B
5.D
6.D
7.D
8.C
9.A
10.D
11.A
12.C
13.A
14.C
15.A
16.C
17.C
18.C
I looked all morning for help on this test but couldn’t find it .. so to anyone who come along after me that needs a lil help... this is for you my friend.. A lil beacon of light when all else seem grim .. sorry I haven’t done the last two question .. lesson 7:probability unit test California connexus 7th grade
like if you think goku could beat one punch mand and dislike if you think one punch man could beat goku
I think goku would win