In a right triangle if sinA=6/7 and cosA=4/7 what is tanA=
7 is the hypotenuse. 4 and 6 are either opposite to or adjacent to angle A. Tangent is opposite/adjacent. Use 4 and 7 to fill in opposite/ adjacent depending on their location.
This question makes no sense.
You don't have a right-angled triangle , since
6^2 + 4^2 ≠ 7^2
from sinA = 6/7 , A = appr 59°
from cosA = 4/7, A = appr 55°
Which one is it ?
To find the value of tan(A), we can use the following formula:
tan(A) = sin(A) / cos(A)
Given that sin(A) = 6/7 and cos(A) = 4/7, we can substitute these values into the formula:
tan(A) = (6/7) / (4/7)
Now, we can simplify this expression by multiplying the numerator and denominator by the reciprocal of the denominator:
tan(A) = (6/7) * (7/4)
Simplifying further, we can cancel out the common factor of 7:
tan(A) = 6/4
Lastly, we can simplify the fraction by dividing both the numerator and denominator by their greatest common divisor, which is 2:
tan(A) = 3/2
Therefore, the value of tan(A) is 3/2.