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A body is thrown vertically upward from the ground with an initial velocity of 96 ft/sec. Find the maximum height attain by the body

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  1. v = Vi - 32 t
    0 = 96 - 32 t
    t = 3 s

    h = Vi t - 16 t^2
    h = 96(3) - 16(3)^2
    h = 288 - 144 = 144 ft

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    posted by Damon
  2. s-maximum height attained by the body in feet
    Vo-initial velocity(ft|sec)
    t-time(sec)

    s=96t-16t^2
    16t^2=96t
    16t^2/16=96t/16
    t^2=6t
    t^2-6t=0
    t^2-6t+9=0
    (t-3)(t-3)=0
    t=3 sec.

    s=96t-16t^2
    s=96(3)-16(3)^2
    s=288-144
    s=144 feet

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