What volume of 12.0 M HCl must be diluted in order to make 250.00 ml of 2.00 M HCl
12(v) = 250(2)
12v = 500
500/12 = 41.66 or (41.67 if u have to round)
To determine the volume of 12.0 M HCl required to make 250.00 ml of 2.00 M HCl, you can use the formula for dilutions:
C1V1 = C2V2
where:
C1 = initial concentration of the HCl solution
V1 = initial volume of the HCl solution
C2 = final concentration of the HCl solution
V2 = final volume of the HCl solution
Let's plug in the given values into the formula:
(12.0 M)(V1) = (2.00 M)(250.00 ml)
Now, solve for V1:
V1 = (2.00 M)(250.00 ml) / 12.0 M
V1 = 41.67 ml
Therefore, you need to dilute 41.67 ml of 12.0 M HCl with enough water to make a total volume of 250.00 ml in order to obtain a 2.00 M HCl solution.
To determine the volume of the 12.0 M HCl solution required to make 250.00 ml of a 2.00 M HCl solution, we can use the dilution formula, which is:
M1 * V1 = M2 * V2
Where:
M1 = initial concentration (12.0 M)
V1 = initial volume (unknown)
M2 = final concentration (2.00 M)
V2 = final volume (250.00 ml)
Now, let's rearrange the formula to solve for V1:
V1 = (M2 * V2) / M1
Plugging in the given values:
V1 = (2.00 M * 250.00 ml) / 12.0 M
V1 = 41.67 ml
Therefore, you would need to dilute 41.67 ml of the 12.0 M HCl solution to make 250.00 ml of a 2.00 M HCl solution.