Find the slope of the line 8x+y=11
Put it in point slope form:
y= -8x + 11
slope: -8
y intercept: 11
Thank you
To find the slope of the line given by the equation 8x + y = 11, we need to rewrite the equation in slope-intercept form, which is in the form of y = mx + b.
To do this, we isolate the y variable on the left side of the equation by subtracting 8x from both sides:
y = -8x + 11
Now that the equation is in slope-intercept form, we can easily identify the slope. In this case, the coefficient of x, which is -8, represents the slope of the line.
Therefore, the slope of the line is -8.
Additionally, the equation allows us to determine the y-intercept, which is the point where the line intersects the y-axis. In this case, the y-intercept is the constant term in the equation, which is 11.
So, the slope of the line is -8, and the y-intercept is 11.