# Chemistry-Dr.Bob222

A 25.0 mL sample of 0.125 M pyridine is titrated with 0.100 M HCl.

Calculate the pH at 0 mL of added acid.

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1. Treat this as just another ammonia, NH3, problem. Remember, NH3 + HOH ==> NH4^+ + OH^- and you know how to solve those problems. This is the same thing.
See here for the structure.
https://en.wikipedia.org/wiki/Pyridine
Let's call pyridine a simple PN. Then
......PN + HOH ==> PNH^+ + OH^-
I.....0.1............0.......0
C.....-x.............x.......x
E....0.1-x...........x.......x

Kb pyr = (PNH^+)(OH-)/(PN)
Substitute the E line and solve for x = (OH^-), then convert to pH.

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