A 25.0 mL sample of 0.125 M pyridine is titrated with 0.100 M HCl.

Calculate the pH at 0 mL of added acid.

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asked by Nevaeh
  1. Treat this as just another ammonia, NH3, problem. Remember, NH3 + HOH ==> NH4^+ + OH^- and you know how to solve those problems. This is the same thing.
    See here for the structure.
    Let's call pyridine a simple PN. Then
    ......PN + HOH ==> PNH^+ + OH^-

    Kb pyr = (PNH^+)(OH-)/(PN)
    Substitute the E line and solve for x = (OH^-), then convert to pH.

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