math

Let a be -1/6 and let b be 1/2. Let x be the sum of the reciprocals of a and b, let y be the product of the reciprocals of a and b, and let z be twice the reciprocal of a divided by the reciprocal of b. Calculate x+y+z.

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  1. reciprocal of -1/6
    =6
    and that of 1/2=2
    a=-6
    b=2
    a+b=x
    -6+2=x
    x=-4
    y=a*b
    y=-6*2
    y=-12
    z=2(a)/b
    z=2*-6/2
    z=-6
    now x+y+z=??

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  2. 97

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