Given the following chemical equation, determine how many grams of N2 are produced by 9.72 g of H2O2 and 6.53 g of N2H4
Where is the equation? And please spell chemistry right next time.
2H2O2(l)+N2H4(l)=4H2O(g)+N2(g)
This is a limiting reagent (LR) problem and you know that because amounts are given for BOTH reactants. First, make sure the equation is balanced.
mols H2O2 = grams/molar mass = ?
mols N2H4 = grams/molar mass = ?
Next, using the coefficients in the balanced equation, convert mols H2O2 to mols N2 produced.
Do the same and convert mols N2H4 to mols N2.
These two values for mols N2 are likely to be different; the correct answer in LR problems is ALWAYS the smaller value and the reagent responsible for that smaller value is called the LR.
Using that value, grms N2 = mols N2 x molar mass N2.
To determine how many grams of N2 are produced, we need to consider the balanced chemical equation and use stoichiometry.
The given balanced chemical equation is:
2 H2O2 + N2H4 -> 3 H2O + N2
From the balanced chemical equation, we can see that 1 mole of N2H4 reacts with 1 mole of N2. Therefore, we need to find the moles of N2H4 and convert it to moles of N2, and then convert moles of N2 to grams.
Step 1: Calculate the moles of H2O2 and N2H4
Moles of H2O2 = mass of H2O2 / molar mass of H2O2
Molar mass of H2O2 = 2*1.01 (H) + 2*16.00 (O) = 34.02 g/mol
Moles of H2O2 = 9.72 g / 34.02 g/mol = 0.286 mol (rounded to three decimal places)
Moles of N2H4 = mass of N2H4 / molar mass of N2H4
Molar mass of N2H4 = 2*14.01 (N) + 4*1.01 (H) = 32.05 g/mol
Moles of N2H4 = 6.53 g / 32.05 g/mol = 0.204 mol (rounded to three decimal places)
Step 2: Determine the moles of N2 produced
From the balanced chemical equation, we see that the stoichiometric ratio between N2H4 and N2 is 1:1. Therefore, the moles of N2 produced will be equal to the moles of N2H4.
Moles of N2 = 0.204 mol
Step 3: Convert moles of N2 to grams
To convert moles of N2 to grams, we need to use the molar mass of N2, which is 2*14.01 = 28.02 g/mol.
Mass of N2 = moles of N2 * molar mass of N2
Mass of N2 = 0.204 mol * 28.02 g/mol = 5.71 g (rounded to two decimal places)
Therefore, 5.71 grams of N2 are produced from 9.72 g of H2O2 and 6.53 g of N2H4.