A river flow of width 100 m is flowing with velocity of 1.5 m/s .A man start from one end with rest relative to river .He raws with an acceleration of 2 m/s^2 relative to the river if the man want to cross river in minimum time by how much distance will he be drifted in the direction of rivet flow during crossing
x = 1/2 at^2 (across)
solve for t
x = vt (downstream)
PS. He's rowing 10 m/s by the end of this. Don't think too many people can row 22 mph....
Oops. I mean 20 m/s. Even more ridiculous.
To determine the distance the man will be drifted in the direction of the river flow during crossing, we can break down the problem into two components: the time it takes to cross the river and the distance drifted during that time.
First, let's calculate the time it takes for the man to cross the river. We know that the river width is 100 m, and the man's velocity relative to the river is 1.5 m/s. Therefore, the time taken to cross the river can be calculated using the formula: time = distance / velocity.
time = 100 m / 1.5 m/s = 66.67 s
Next, we need to calculate the distance drifted during that time. The man's acceleration relative to the river is 2 m/s^2. We can use the formula: distance drifted = 1/2 * acceleration * time^2.
distance drifted = 0.5 * 2 m/s^2 * (66.67 s)^2 = 4444.45 m
Therefore, the man will be drifted by approximately 4444.45 meters in the direction of the river flow during crossing.