# Chemistry

What is the delta G naught for the cell in question 1 at 298 K?

Question 1: Which is spontaneous, the oxidation of copper to Cu2+ or the reduction of Cu2+ to Cu?

Work:
OX: Cu --> Cu2+ + 2e-
RE: 2e- + Cu2+ --> Cu
Overall: Cu + Cu2+ --> Cu + Cu2+

Delta G knaught = -RTln(Keq)
= -(8.314)(298)ln(1)
= 0?
R=8.314 J/Kmol
T=298 K
Keq= [Cu2+]/[Cu2+] = 1

The problem I am having is with the Keq. I think its one, but that would make the entire delta G knaught 0? I am just a bit confused.

1. 👍 0
2. 👎 0
3. 👁 145
1. You have no concns listed so you can't get Keq that way.
Use dGo = -nEoF
You will need to look up the value of Eo for the reaction. Obviously the one with Eo a positive number will give you a negative dGo and that is the one that is spontaneous. If you want Keq, you can get that AFTER you know dGo by
dGo = -RTlnK.

1. 👍 0
2. 👎 0

## Similar Questions

1. ### chemistry

Determine delta G naught at 298.15K for a 0.50 V voltaic cell if n=3 for that cell.

asked by Kaitlin on April 18, 2016
2. ### Inorganic chemistry

E naught cell for the following galvanic cell is +0.254V Hg2^2(aq)+2I^-(aq) ==> 2 Hg(l) + I2(s) What is delta G naught for this reaction? Delat G naught = -nFEnaught n = the number of moles of electrons transferred between

asked by Steve on April 14, 2009
3. ### Chemistry, Thermodynamics

I have a couple questions: 1. When analyzing which has greater entropy, do you look at the larger number or the smaller number? 2. What two things must be met for a reaction to be spontaneous under ALL temperature conditions? 3.

asked by Taasha on August 10, 2007
4. ### Inorganic chemistry

Calulate E naught cell for the reaction below 5 Cd(s) + 2 MnO4^-(aq) + 16H+(aq)+ 2 Mn2+(aq) + 8 HxsO(l) The oxidation anode must be 5Cd(s) ==> 5Cd2+(aq) +10e^- The reduction cathode must be 2MnO4^- + 16H2^=(aq) + 10e^- ==>

asked by Steve on April 14, 2009
5. ### chemistry---

What is the equilibrium constant for the redox reaction in question 3? Combining the two equations for ∆Go below ∆G= −n F Ecell and ∆G= −R T ln K gives −n F E cell = −R T ln K... The ecell from question three was

asked by EBB on April 28, 2016
6. ### Inorganic chemistry

Consider the half-reactions: Cu^2+(aq) +2e^- ==> Cu(s) E naught = +0.34V Sn^2+(aq) + 2e^- ==> Sn E naught = -0.14V Fe^2+ + 2e^- ==> Fe(s) E naught = -0.44V Al^3+(aq) = 3e^- ==> Al(s) E naught = -1.66V Mg^2+(aq) = 2e^- ==> Mg(s) E

asked by Steve on April 11, 2009
7. ### Inorganic chemistry

Calculate E naught cell for the reaction b 5Cd(s) + 2MnO4-(aq) + 16H+(aq) ==> 5Cd^2+(aq) = 2Mn^2+(aq) + 8H2O(l) given the following standard reduction potentials MnO4^-(aq) + 8H^+(aq) = 5e^- ==> Mn^2+(aq) + 4 H2O(l) E naught =

asked by Steve on April 11, 2009
8. ### Inorganic chemistry

E naught cell for the following galvanic cell is +0.254V. Hg^2+(aq) + 2I^-(aq) ==> 2 Hg(l) +I2(s) What is the change G naught for this reaction?

asked by Steve on April 11, 2009
9. ### biochemistry

Calculate the delta G naught prime f (free energy of formation) of the following compounds at 25 degrees celsius. ethyl acetate (ethyl acetate + H2O ethanol + acetate- + H): delta G naught prime =-19.7 kj/mol); the pka of acetic

asked by meraki on September 8, 2013
10. ### Chemistry

The multiple Choice Question: Determine delta G (free energy at standard condition s) for the reaction below, considering Kp = 8 at 25 degrees celcius. 2Ag -> B The answer Choices: A.-2.303 x (0.287) x (25) x log 8 [J] B.-2.303 x

asked by Tommy on April 22, 2007

More Similar Questions