using the following set of data, calculate the lower quartile, the upper quartile, and the interquartile range.20, 22, 25, 28, 29, 30, 32, 33, 34 ?
NEED HELP !
I am in sixth grade not college
my head will start bleeding after this
WHAT THE HECK IS THIS?! IM IN 6TH GRADE, not college or the smartest school in the world
I am lost.😳
Aight' let's do this.
Step 1. Normally, the first thing you would do would be to organize the numbers from least to greatest. But that's already done. Find the median of the numbers. In this case, that would be 29 since it's in the middle.
Step 2. For the lower quartile, add 22 and 25 together to get 47. Divide 47 by 2 to get 23.5.
To get the upper quartile, add 32 and 33 together to get 65. Divide 65 by two to get 32.5.
I dont know the rest
Who else tried coping and pasting
Say what?!?!?🤯
Same here
So which one
Why cant people just say the exact answer without confusing us
helllpppp
this is hell!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!11
hmm I'm behind on a lot, this quiz is in the way of it all
Or used other method using Percentile method
Q1 = 25%
Q3 = 75%
ARRANGE FIRST THE DATA TO LOWEST TO HIGHEST .
1. 2. 3. 4. 5. 6. 7. 8. 9
20 22 25 28 28 30 32 33 34
For Q1
N=9 P = 25
Note: if C is greater than whole # round off to the next highest #.
C1= (N x P)/100 = 2.25 = 3
So then
Q1 = 25
C3 = (9× 75 )/100 = 6.75 = 7
Q3 = 32
IQR = (Q3-Q1)/2 = (32-25)/2 = 3.5
Final answer
Lowest quartile = 25
Highest quartile = 32
IQR = 3.5
What is the interquartile range??
The inter quartile range is the middle so the answer is 29
First you find the median (which is 29) and that is you interquartile
To find the lower quartile you add 20+25=47, then divide 47/2 to get 23.5
To find the upper quartile you add 32+33=65 the divide 65/2=32.5
Plz put this in your own words I worked hard on this
Yah u need to either gimmi da answers or im done
I came on here because i did not feel like doing the work even though i know how to solve this. (This problem is asking you for the coordinates of a box and whisker plot) Everyone listen to IDK this myself but ill try to help or you can go to lesson 3 unit 4 the lesson name is tables and plots it tals all about these type of of problems on page 3. i really hope i helped if none of this helped go to Live teacher time at 3:00 with your math teacher. have a good day everyone even if you don't finish the quiz today you have spring break and Monday to finish this;) don't be hard on yourself ;)
Here are some things to help with this problem!
A box-and-whisker plot is a graph that shows five values from a set of data: the highest and lowest numbers, the median, which divides the data into two halves, and the quartiles, which divide the data into fourths.
These are the steps you would follow to make a box-and-whisker plot
Find the median of the data.
( Example of numbers )6, 8, 10, 12, 14, 18, 25, 35, 45, 50
There are two values in the middle, 14 and 18. The mean of these two numbers is 14+18/2=16
The median of this set of numbers is 16
Find the lower quartile, which is the median of the lower half of the data.
6, 8, 10, 12, 14
10 is the median of the lower half of the data.
Find the upper quartile, which is the median of the upper half of the data.
18, 25, 35, 45, 50
35 is the median of the upper half of the data. The middle quartile is 16, the lower quartile is 10, and the upper quartile is 35.
I worked really hard on this comment please dont put hate comments🥺🙏🏿 i hope you guys end up understanding everything have a good day!
ok ok ok people go back to the lesson it explains it go to a different tab or open notes your fine ask a teacher if you still don't know also people who came here for the answer your supposed to learn this is why your confused because you did not work hard enough or care enough to learn the materials.
But still, whats the interquartile range?
make sure to put it in your own words or else you wont get a full grade :)
The lower quartile is 23.5
The upper quartile is 32.5
The interquartile range is 9
Step-by-step explanation:
The given data set is 20, 22, 25, 28, 29, 30, 32, 33, 34.
The data set is already sorted in ascending order.
The middle number of this data set is called the median.
Therefore the median is 29.
The median divides the data set into two halves.
The lower half is
20, 22, 25, 28
The median of the lower half is the lower quartile.
The upper half is 30, 32, 33, 34
The median of the upper half is the upper quartile.
The interquartile range is given by
Brainly.com let you copy and paste
Helppppppppppp!!!!!!!!!!!!!!!!!!!!!!!!!!!!!meeeeeeeeeeee pleaseeeeeeee.!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Order the data from least to greatest.
Find the median of the data set and divide the data set into halves.
Find the median of the two halves=14.5
At least tell me how to solve i do not just need the answers
my brin hurtssssssss
Hang in there everybody milestone are near and summer is soon!!
i hate math.
OHHH OK TYSM I PASSED :D
Howwww
how do you do that i need help
Whats the Inter quartile range
20 plus 25 doesn't equal 47 it equals 45 ????
Im giving up on my dream, why the heck do i have this damned question on connexus
I'M IN 6TH GRADE WHY IS THIS IN MY MATH TEST!??!?!?!?!?!?!?!??!?!?
1st find the median, which would be the middle of the data set. Since there are 9 numbers the median would be the middle number of the set, this would give you the same amount of numbers on each side of it. The numbers to the left would be the lower and the numbers on the right would be the upper
so in the given data set the median is 29
the lower quartile is the median of the lower numbers, in this case the numbers below 29 are 20, 22 , 25, 28
since there is an even amount of numbers you need to add the 2 middle numbers together and divide by 2 to find the lower quartile so 22 +25 = 47, 47 / 2 = 23.5 this is the lower quartile
the upper quartile is found the same way, but using the upper numbers so in this case using 30, 32, 33 , 34
add the 2 middle numbers 32 +33 = 65 divide by 2 = 65/ 2 = 32.5 this is the upper quartile
the inter quartile range is subtracting the lower quartile from the upper quartile: 32.5 - 23.5 = 9
9 is the inter quartile range
To find the outliers, you can use the formula:
Lower outlier = Q1 - 1.5(IQR)
Upper outlier = Q3 + 1.5(IQR)
In this case, Q1 = 23.5, Q3 = 32.5, and IQR = 9.
Lower outlier = 23.5 - 1.5(9) = 9.5
Upper outlier = 32.5 + 1.5(9) = 46
So any values below 9.5 or above 46 would be considered outliers. However, in this data set, there are no values that fall outside of this range, so there are no outliers.
thank you
You're welcome! Let me know if you have any other questions.
I'm sorry to hear that. Math can be challenging, but with practice and patience, it can also be rewarding. If you ever need help with math, don't hesitate to ask for assistance from your teacher, tutor, or online resources.
To find the mean absolute deviation for the high temperatures in the given data, follow these steps:
Step 1: Find the mean of the set of data by adding all the temperatures and dividing by the total number of temperatures.
Mean = (49 + 55 + 52 + 46 + 47 + 42 + 38) / 7
Mean = 46.4
So the mean temperature for the week is 46.4 degrees Fahrenheit.
Step 2: Find the distance of each number from the mean by subtracting the mean from each temperature and taking the absolute value.
Distance from mean = |temperature - mean|
For example,
Distance from mean for Sunday = |49 - 46.4| = 2.6
Complete this step for each day of the week.
Sunday: |49 - 46.4| = 2.6
Monday: |55 - 46.4| = 8.6
Tuesday: |52 - 46.4| = 5.6
lol same @hey lads
I got a 100% (Idk myself, but I'll try to help) is correct
"@Idk Myself, I'll try to help". He is the helper for this question everyone has.
The interquartile range IQR is the range in values from the first quartile Q1 to the third quartile Q3. Find the IQR by subtracting Q1 from Q3.
IQR = Q3 - Q1
@ i got yo back bae
Is right I got the same answer.
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what is the name of the people with the right answers?
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ok then tell me that
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WHAT ARE THOSE MULTIPLE USERS USER NAMES!
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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Day Sunday Monday Tuesday Wednesday Thursday Friday Saturday
Temperature (degrees F) 49 55 52 46 47 42 38
Julia measured the high temperature in her town for one week. Using the chart above, find the mean absolute deviation for the high temperatures. Round your answer to the nearest tenth.
Be sure to show your work for finding:
the mean of the set of data
the distance of each number from the mean
the mean absolute deviation
Thant's the next question for the assignment
I apologize for the confusion. Please provide me the question for which you need assistance.
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Day Sunday Monday Tuesday Wednesday Thursday Friday Saturday
Temperature (degrees F) 49 55 52 46 47 42 38
Julia measured the high temperature in her town for one week. Using the chart above, find the mean absolute deviation for the high temperatures. Round your answer to the nearest tenth.
Be sure to show your work for finding:
the mean of the set of data
the distance of each number from the mean
the mean absolute deviation
Thank you so much bot
N= # of data = 9
C.I= class interval= (R/K)
Note : K= 1 + 3.322 log (N)
R= highest # - lowest #
C.I = (34-20)/(1 + 3.322 log (9))
C.I = 3.357(used whole #) = 4
C.B = class boundary
CF = cumulative frequency
f(frequency)= data inside the C.I
DATA TABLE
C.I C.B f <C.f
20-24 19.5-24.5 2 2
25-29 24.5-29.5 3 5
30-34 29.5-34.5 4 9
Q1= lower quartile
Q3 = highest quartile
IQR = interquartile range
I= 25-20= 5(CONSTANT)
NOTE: Lb,F,fm will vary at clue
Q1=Lb + ( (1N/4)-F / fm )(I)
Clue :1(N)/4 =9/4 =2.25(greater 2)
So I will look the Lb,F,fm align at 5 <cf ( look at table )
Lb=can be found at lower C.B= 24.5
F =lower of 5 (>c.f) =2(>cf) = 2
Fm = its frequency align = 3
Q1 =24.5 +( (9/4)-2 / 3 )×(5)
Q1 = 24.9167
Q3 = Lb + ( (3N/4)-F / fm)×(I)
Clue :(3N/4) = ((3×9)/ 4 )= 6.75
So Lb, F, fm is align at 9 (> cf)
Lb = 29.5
F = lower of 9 (>cf) = 5
Fm = 4
Q3 =29.5 +( ((3×9)/4)-5)/4 )×(5)
Q3 = 31.6875
I.Q.R = (Q3-Q1)/2 = 3.3854
Final answer
Lowet quartile = 24.9167
Hghest quartile = 31.6875
IQR = 3.3854