When a rocket is 3km above the ground,it has an upward velocity of 10 m.s^-1.A booster rockect is fired downward,resulting in a net force of 6000 N being exerted upward on the shuttle.The time it takes the booster to leave the shuttle after being fired is 2,5 seconds.if the mass of the shuttle is 2000 kg,
calculate the velocity of the shuttle immediately afta the booster is fired
I guess net force includes gravity down so
Force * time = change of momentum
6000 * 2.5 = 2000 (v-10)
Where is your attempted solution? I refuse to help you until you post it
To calculate the velocity of the shuttle immediately after the booster is fired, we need to find the change in velocity caused by the booster. We can do this using Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
Here's how we can solve the problem step by step:
Step 1: Calculate the acceleration of the shuttle caused by the booster.
From the given information, we know that the mass of the shuttle (m) is 2000 kg, and the net force (F) exerted on the shuttle is 6000 N. We can use Newton's second law of motion to find the acceleration (a) of the shuttle:
F = m * a
6000 N = 2000 kg * a
a = 6000 N / 2000 kg
a = 3 m/s²
Step 2: Determine the change in velocity.
The booster is fired for a time of 2.5 seconds. During this time, the shuttle is accelerating due to the net force exerted by the booster. We can use the equation for constant acceleration to calculate the change in velocity (Δv) of the shuttle:
Δv = a * t
Δv = 3 m/s² * 2.5 s
Δv = 7.5 m/s
Step 3: Calculate the velocity of the shuttle immediately after the booster is fired.
The rocket initially had an upward velocity of 10 m/s. Since the booster was fired downward, we subtract the change in velocity caused by the booster from the initial velocity to find the final velocity (v) of the shuttle:
v = 10 m/s - 7.5 m/s
v = 2.5 m/s
Therefore, the velocity of the shuttle immediately after the booster is fired is 2.5 m/s.