can someone check my labels for the reaction of a radical with an extra electron, (R(e-)) and an antioxidant, ArOH.
R(e-) + ArOh --> RH + ArO(e-)
R(e-) is oxidizing agent.
ArOH is reducing agent.
RH is reduced
ArO(e-) is oxidized.
Is this correct?
And the other possible reaction,
R(e-) + ArOH --> R- + ArOH(e-)+
R(e-) is reducing agent.
ArOH is oxidizing agent
R- is oxidized
ArOH(e-) is reduced. ?
Let's analyze the given reactions and check if your labels for the reactants and products are correct.
In the first reaction, R(e-) (which represents a radical with an extra electron) reacts with ArOH (an antioxidant) and forms RH (a reduced compound) and ArO(e-) (an oxidized compound).
You correctly labeled R(e-) as an oxidizing agent because it is involved in oxidizing the antioxidant (ArOH) to ArO(e-). Likewise, ArOH is correctly labeled as a reducing agent since it donates an electron to reduce R(e-) to RH. RH is correctly labeled as the reduced compound, and ArO(e-) is labeled as the oxidized compound.
Overall, your labels for the first reaction are correct.
Moving on to the second reaction, we have R(e-) reacting with ArOH. This time, the reaction produces R- (an oxidized compound) and ArOH(e-) (a reduced compound).
You labeled R(e-) as a reducing agent, which is not correct in this case. It should be labeled as an oxidizing agent because it oxidizes ArOH to ArOH(e-). Conversely, ArOH is the reducing agent as it donates an electron to reduce R(e-) to R-. R- should be labeled as an oxidized compound, and ArOH(e-) as a reduced compound.
To summarize:
- In the first reaction, R(e-) is the oxidizing agent, ArOH is the reducing agent, RH is the reduced compound, and ArO(e-) is the oxidized compound.
- In the second reaction, R(e-) is the oxidizing agent (not reducing agent), ArOH is the reducing agent, R- is the oxidized compound, and ArOH(e-) is the reduced compound.
Therefore, the corrected labels for the second reaction are as follows:
- R(e-) is the oxidizing agent.
- ArOH is the reducing agent.
- R- is the oxidized compound.
- ArOH(e-) is the reduced compound.