physics

A 3580 Hz tuning fork is sounded at the same time that a note on a piano is struck. You hear 8 beats/s. You loosen the string slightly and now hear 12 beats/s. What is the frequency of the vibrating piano string now after the loosen ing?

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asked by Jay
  1. you hear the difference frequency
    8 = 3580 - f
    f = 3472 original

    12 = 3580 -f
    f = 3568 final
    good, the frequency went down when I loosened the string

    so 3568 Hz

    WHAT if I wrote the difference the other way (all I know is the absolute value)
    8 = f - 3580
    f = 3588
    12 = f - 3580
    f = 3592
    oh my the frequency went up when we loosened the string - no way so the difference is the other way around
    and
    3568 is the answer

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    posted by Damon

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