Fluorine-20 has a half-life of 11.0 s. If a sample initially contains 49.0 μg of this isotope, how much remains after 66.0 s ?

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asked by susan
  1. 66s is 6 half-lives, so

    49.0 * (1/2)^6 = 0.765 μg

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    posted by Steve

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