A block of mass 6 kg is accelerating at 1.25 m/s ,on the horizontal surface, under the action of a horizontal force of magnitude 22.5 N . Calculate the coefficient of friction between the block and the surface.
Wb = M*g = 6 * 9.8 = 58.8 N. = Wt. of block = Normal(Fn).
Fap-Fk = M*a, 22.5-Fk = 6*1.25 = 7.5, Fk = 15 N. = Force of kinetic friction.
u = Fk/Fn = 15/58.8 = 0.255.
To calculate the coefficient of friction between the block and the surface, we can use the formula:
μ = (F - ma) / (mg)
Where:
- μ is the coefficient of friction
- F is the applied horizontal force
- m is the mass of the block
- a is the acceleration of the block
- g is the acceleration due to gravity (approximated as 9.8 m/s^2)
Given:
- F = 22.5 N
- m = 6 kg
- a = 1.25 m/s^2
- g = 9.8 m/s^2
Substituting the given values into the formula, we get:
μ = (22.5 - (6 * 1.25)) / (6 * 9.8)
Simplifying the equation further:
μ = (22.5 - 7.5) / 58.8
μ = 15 / 58.8
μ ≈ 0.255
Therefore, the coefficient of friction between the block and the surface is approximately 0.255.