What is the OH- concentration of a solution whose pH is 12.40?

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  1. Trinity,

    from the pH you can determine the H3O^+ concentration by using ph=-log[H3O^+]. Then you can use Kw=KaxKb to solve for OH- concentration

    10^-12.40 = 10^log[h3o^+] =
    4.0x10^-13 M = [h3o^+]

    Now use 4.0x10^-13[OH^-] = 1.00x10^-14 =

    [OH^-]= 2.5X10^-2 M

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  2. thanks@ Michael

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  3. pH + pOH = pKw = 14.
    You know pH, solve for pOH.
    Then pOH = -log(OH^-)
    Substitute and solve for OH. You should get a little less than 2 but that's just an estimate.

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  4. Thanks @ DrBob222

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  5. I hit the wrong key. The answer should be a little less than 3.

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  6. If [H3O+] = 1.7 x 10–3 M, what is the pH of the solution?

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