Question

At the end of Summer, Puss discovers that his radiator antifreeze solution has dropped below the safe level. If the radiator contains 4 gallons of a 25% antifreeze solution, how many gallons of pure antifreeze must he add to bring it up to a desired 50% solution? how to solve this and please solution

Answer 1

The new capacity is 4+x=y

Where x is the pure anti-freeze,
y is the total capacity.

4+x=y
0.25(4)+x=0.5y

1+x=2+0.5x
x=2

He needs to add 2 gallons of pure anti-freeze.

Answer 2

No 2 gallons is the correct answer.

Answer 3

No, its 2

Answer 4

its 2.

Answer 5

The answer is 2

Answer 6

i do not think that the answer to this question is 4/3 the quoins asks

how many gallons of pure antifreeze must he add to bring it up to a desired 50% solution?

Answer 7

its 2

Answer 8

its 2 :)

Answer 9

thanks

Answer 10

it's right genius answer right there

Answer 11

The correct answer is definitely 2. John is absolutely correct.

Answer 12

I'm giving everyone who said 2 gallons a thumbs up!!! correct!!!

Answer 13

Yep 2 gallons is 100% correct

Answer 14

It has to be 2

Answer 15

Dude the answer is 2 bro

Answer 16

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Answer 17

can someone please find the right answer plz plz plz

Answer 18

Idk pls help

Answer 19

NO THE RIGHT ANSWER IS 69 OR 420

Answer 20

thanks you sooooooooooo much!

Answer 21

Let the amount of old stuff drained by x gallons

so you have 4-x gallons left of 25% solution

.25(4-x) + x = .5(4)
1 - .25x + x = 2
.75x = 1
(3/4)x = 1
x = 4/3

so drain 4/3 gallon of the current solution, then top it up with pure antifreeze