Chemistry

If a mothball (C10H8) has a mass of 1.32 grams, how many naphthalene molecules does it contain?

If I'm right just multiply 1.32g by 6.022*10^23 and the answer is 7.949*10^23 molecules.
Is this right?

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  1. Close but no cigar.
    It is not a gram that contain 6.022E23 but a MOLE that contains 6.022E23.
    So convert that 1.32 g to mols.
    mols = grams/molar mass = ?.
    Then that many mols x 6.022E23 molecules/mol = # molecules of C10H8..

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  2. Okay,
    so 1.32/128.164=.0103
    0.0103*6.022*10^23=6.2*10^21 molecules
    ?

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  3. Yes it's correct

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