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The parallel sides of a trapezium have lenghts 5cm and 8cm..The other two sides have the lenghts 6cm and 4cm..Find the angles of the trapezium?

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  1. If AB=8 and DC=5, then if the altitude is h,

    h = 4sinA = 6sinB

    h cotA + 5 + h cotB = 8
    4 sinA cotA + 5 + 6 sinB cotB = 8
    4cosA + 5 + 6cosB = 8
    4cosA + 6cosB = 3

    solve for A and B.

    Note that D = (90-A)+90 = 180-A
    and similarly for C.

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