Algebra

Form a third degree polynomial function with real coefficients such that -7 + i and -9 are zeros

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  1. the -7 + i has a conjugate partner of -7 - i
    so (-7+i)(-7-i)
    = 49 - i^2
    = 50
    -7+i + (-7-i)
    = -14
    so we can form the quadratic as
    x^2 + 14x + 50 as one of the factors.
    the other is (x+9)

    so the polynomial could be
    f(x) = (x+9)(x^2 + 14x + 50)

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