calculus

Find the solution of the differential equation that satisfies the given initial condition.
dp/dt=2 sqrt(pt), P(1)=5

my answer: P=(2/3t^(3/2)+(15sqrt(5)-10)/15)^2

how is it wrong?

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  1. dp/dt = 2√(pt)
    dp/√p = 2√t dt
    2√p = 4/3 t^(3/2) + c
    p = (2/3 t^(3/2) + c)^2

    Now plug in t=1 to find c.

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