"If a skier coasts down a slope at an angle of 24 degrees below the horizontal, what is her acceleration if the force of friction is negligible?"

I must have done this question 15 times, and still can't get the right anwser. Can anyone help me?

1. say she has mass m
there is a gravitational force down on her = m g
that force has a component normal (perpendicular) to the snow)=mg cos 24
there is an equal and opposite force up from the snow = mg cos 24
because there is no acceleration into or out of the snow.
HOWEVER, that gravitational force has another component down the slope = m g sin 24
There is no equal and opposite force to resist that because she is free to accelerate down the slope.
so
F = m a = m g sin 24
so
a = g sin 24
and sin 24 is about .407

posted by Damon
2. Thank you so much; once I drew my slope levels correctly, it was no problem. Thanks again!

posted by solexgirl12

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