four 240ohms light bulb are connected in series, what is the total resistance of the circuit and what is their resistance if they are connected in parallel
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To find the total resistance of the circuit when the four 240-ohm light bulbs are connected in series, you simply add up their individual resistances.
In a series circuit, the current has only one path to flow through, and the total resistance is equal to the sum of the individual resistances.
So, if all four 240-ohm light bulbs are connected in series, the total resistance of the circuit would be:
Total Resistance = 240 ohms + 240 ohms + 240 ohms + 240 ohms
Total Resistance = 960 ohms
Now let's consider the situation where the four light bulbs are connected in parallel.
In a parallel circuit, each component has its own separate branch, allowing the current to flow through multiple paths independently. The total resistance in a parallel circuit is calculated differently.
When resistors are connected in parallel, the reciprocal of the total resistance is equal to the sum of the reciprocals of the individual resistances.
So, if all four 240-ohm light bulbs are connected in parallel, the total resistance of the circuit would be:
1 / Total Resistance = 1 / 240 ohms + 1 / 240 ohms + 1 / 240 ohms + 1 / 240 ohms
To simplify this calculation, we can use the formula for calculating the total resistance of resistors connected in parallel:
1 / Total Resistance = (Number of Resistors) / (Individual Resistance)
Plugging in the values, we get:
1 / Total Resistance = 4 / 240 ohms
Total Resistance = 240 ohms / 4
Total Resistance = 60 ohms
Therefore, when four 240-ohm light bulbs are connected in series, the total resistance is 960 ohms, and when they are connected in parallel, the total resistance is 60 ohms.