Math

John chooses a 5-digit positive integer and deletes one of its digits to make a 4-digit number. The sum of this 4-digit number and the original 5-digit number is 52713. What is the sum of the digits of the original 5-digit number?

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  1. Solved it!!

    Five options possible are:
    1. abcde + abcd
    2. abcde + abce
    3. abcde + abde
    4. abcde + acde
    5. abcde + bcde
    But as last digit of sum is 3 then only (1) is possible. (e + e – cannot be an odd number)
    a must be 4 or 5
    Then work out using 4 and 5. ‘a’ has to be 4.

    47921
    +4792 = 52713
    So answer is 23 (4+7+9+2+1)

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  2. I think it should be 5+7+9+2+1=24

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  3. the answer is 23 confirmed.

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  4. I agree with 47921 plus 4792

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  5. Ha ha.You are cheating in math kangaroo.You searched up the question didn't you?If you did not then you are a good person if you did it is okay.I did that too because I could not solve it.It is really simple.All you have to do is just work it out and your answer is C(23)LoL everyone else explained it so don't worry.

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  6. I have a awesome response

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  7. At least I think so.

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  8. Have not given complete solution

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