find the volume of iron required to make an open box whose ,external dimensions are 36 cm *25 cm *16.5 cm, the box being 1.5 cm thick throughout . if 1 cm ^3 of iron weights 8.5 grams , find the weight of the empty box in kilogramsfind the volume of iron required to make an open box whose ,external dimensions are 36 cm *25 cm *16.5 cm, the box being 1.5 cm thick throughout . if 1 cm ^3 of iron weights 8.5 grams , find the weight of the empty box in kilograms
3960cm3,33.66kg
3970
why the h eight is not reduced by 3 ??
To find the weight of the empty box, we first need to calculate its volume.
1. The external dimensions of the box are given as: length = 36 cm, width = 25 cm, and height = 16.5 cm.
2. The box is 1.5 cm thick throughout, so we need to subtract twice the thickness from each dimension to get the inner dimensions. Inner dimensions: length = 36 cm - 2 * 1.5 cm, width = 25 cm - 2 * 1.5 cm, and height = 16.5 cm - 2 * 1.5 cm.
Let's calculate the inner dimensions:
- Length: 36 cm - 2 * 1.5 cm = 36 cm - 3 cm = 33 cm
- Width: 25 cm - 2 * 1.5 cm = 25 cm - 3 cm = 22 cm
- Height: 16.5 cm - 2 * 1.5 cm = 16.5 cm - 3 cm = 13.5 cm
3. The volume of the empty box is calculated by multiplying the length, width, and height of the inner dimensions. Volume = length * width * height = 33 cm * 22 cm * 13.5 cm.
Let's calculate the volume:
- Volume: 33 cm * 22 cm * 13.5 cm = 9774 cm³
4. Given that 1 cm³ of iron weighs 8.5 grams, we can now calculate the weight of the empty box. Weight = Volume * Weight per cm³.
Let's calculate the weight:
- Weight: 9774 cm³ * 8.5 grams/cm³
To convert the weight from grams to kilograms, we divide by 1000.
Let's calculate the weight in kilograms:
- Weight: (9774 cm³ * 8.5 grams/cm³) / 1000 = 83.039 kilograms
Therefore, the weight of the empty box is 83.039 kilograms.