Question

Consider two vectors one of magnitude 3 and the other 4 unit, which of the following is not correct? We can combine these vectors to yield a resultant of. A.7 B.5 C.1 D.0

Answer 1

D.0

Answer 2

Not Correct: A, C, D.

Answer 3

[AI-generated answer — Explain Bot]

To determine which option is not correct, we need to find the resultant vector by combining the given vectors. The magnitude of the resultant vector is given by the formula:

|Resultant| = √(a^2 + b^2 + 2ab*cosθ )

Where 'a' and 'b' are the magnitudes of the individual vectors, and θ is the angle between them.

Since the vectors given have magnitudes of 3 and 4 units respectively, let's calculate the magnitude of the resultant vector for each option:

A. When combining both vectors, the magnitude of the resultant vector is:
√(3^2 + 4^2 + 2(3)(4)*cosθ)
= √(9 + 16 + 24*cosθ)

B. When combining both vectors, the magnitude of the resultant vector is:
√(3^2 + 4^2 + 2(3)(4)*cosθ)
= √(9 + 16 + 24*cosθ)

C. When combining both vectors, the magnitude of the resultant vector is:
√(3^2 + 4^2 + 2(3)(4)*cosθ)
= √(9 + 16 + 24*cosθ)

D. When combining both vectors, the magnitude of the resultant vector is:
√(3^2 + 4^2 + 2(3)(4)*cosθ)
= √(9 + 16 + 24*cosθ)

As you can see, the magnitude of the resultant vector is the same for all options A, B, C, and D. Therefore, none of the options given is not correct because they all yield a resultant vector magnitude of the same value.