# Math

A father is 5 times as old as his son.In 4 years the sum of their ages will be 56.Find their present ages.

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1. F = 5(s) //F = father, s = son
F + 4 + s = 56
5s + 4 + s = 56
6s + 4 = 56
6s = 52
s = 8 (approx)

Son = 8 yrs
Father = 40 yrs.

Check:
F = 5(s) = 5(8) = 40
S = 8

40+4 = 44
8+4 = 12

44+12 = 56.

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