How many cubes with 1/2 inch side lengths will fit inside a prism with a volume of 56 cubic inches?
I'm thinking 112, since 56 * 2 =112, but I'm not sure if that's the right thinking.
each 1" cube holds eight 1/2" cubes, not 2/
You don't say what kind of a prism.
I will assume it is a rectangular prism, (fancy word for box)
each cube has a volume of (1/2)^3 or 1/8 inches^3
number that will fit the box = 56/(1/8)
= 448 cubes
e.g. the box could have been
4 in by 7 in by 2 in
for a volume of 56 inches^3
since each cube is 1/2 inch, we could lay 8 along the width, 14 along the length, and stack them 4 high
8x14x4 = 448
hey how do you find the area if a iphone
How many cubes with a side length of 1/2 in. Will fit inside the rectangular prism
honestly itseasy u just have to do it
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To determine how many cubes with 1/2 inch side lengths can fit inside a prism with a volume of 56 cubic inches, you need to consider the volume of both the prism and the cube.
First, let's find the volume of the cube. The volume of a cube formula is V = s^3, where 's' is the length of one side. In this case, the side length is 1/2 inch.
V_cube = (1/2)^3 = 1/8 cubic inches.
Now, let's divide the volume of the prism by the volume of the cube to find the number of cubes that can fit.
Number_of_cubes = Volume_of_prism / Volume_of_cube
Number_of_cubes = 56 cubic inches / (1/8) cubic inches.
To divide by a fraction, we multiply by the reciprocal, so we can rewrite this as:
Number_of_cubes = 56 cubic inches * (8/1).
Number_of_cubes = 448.
So, there are 448 cubes with 1/2 inch side lengths that can fit inside the prism with a volume of 56 cubic inches.