algebra

You invested ​$27,000 in two accounts paying 2% and 3% annual​ interest, respectively.If the total interest earned for the year was $ 800, how much was invested at each​ rate?

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  1. x + y = 27000

    .02x + .03 y = 800

    Interest = amount times rate times time

    Usually people multiply by 100 to get rid of the decimals.
    x + y = 27000
    2x + 3y = 80000

    Multiply the first equation by -2

    -2x-2y =-54000
    2x + 3y = 80000
    add the two equations together to solve for y which tells you how much was invested at 3%.

    Subtract that from the 27000 to find out how much was invested at 2%

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