I am assuming you intended to write 0.1 M and not 0.1 m. M stands for molarity; m stands for molality. Chemistry is more exact than writing sentences with no cap and formulas with no caps. CO, Co, and co all mean different things. May I suggest you find the caps key on your keyboard and use it.
mols = M x L = ?
analysis of a mixture of carbonate and bicarbonate: I did an experiment where 2.306g of unknown was diluted with distilled water to 250ml. Then 3 25mL samples of this unknown were titrated with .0663 M HCl and end point volumes
a solution of HCL is approximately 0.1M and has to be standardized . 1.234g Na2CO3 are dissolved to make 100ml of solution. 20mL of this solution are titrated with the HCL solution, requiring 31.3mL for the second equivalence
Sodium carbonate reacts with nitric acid according to the following equation: Na2CO3+2HNO3-->2NaNO3+CO2+H2O a. how many moles of Na2CO3 are required to produce 100.0 g of NaNO3? b. if 7.50g of Na2CO3 reacts, how many moles of
A 1.213g sample of an unknown weak monoprotic acid was titrated to the endpoint with 27.25mL of a 0.3016M NaOH Calculate: -the number of moles of base reacted. -the number of moles of acid originally present. -the molar mass of
Question: An unknown mass of (NH4)2CO3 is mixed with 4g of NaOH and dissolved in 100cm3 of water,which results a clear solution.Gasses are removed by heating the final solution. 2 parts of 25cm3 of final solution is taken and one