Quick calc question

Given that the antiderivative of f of x equals 1 divided by x is F(x) = Ln|x| + C, evaluate the integral from 1 to 2 of the 1 divided by x, dx.

ln3
1/2
-1/2
ln2

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  1. ∫1/x dx from 1 to 2
    = lnx | from 1 to 2
    = ln2 - ln1
    = ln2 , since ln1 = 0

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