# Maths

The probability that I have to wait at the traffic lights on my way to school is 0.45. Find the probability that on 3 consecutive mornings I have to wait:

A) Once

B) Twice

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1. A) prob(waiting once out of 3)
= C(3,1)(.45)(.55^2)

B) Prob(waiting twice of 3 days)
= C(3,2) (.45^2)(.55)
= ...

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2. 👎 0
posted by Reiny

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